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Nameerror name spark is not defined of Technology

Sorted by: 59. You've imported datetime, but not defined.

On the 4th line, you define the variable config (by assigning to it) within the scope of the function definition that started on line 1. Then on line 11, outside the function (notice indentation), you try to access a variable named config in global scope (and refer to its attribute yaml) - but there isn't one.. Probably you didn't mean to access the variable …I m executing the below code and using Pyhton in notebook and it appears that the col() function is not getting recognized . I want to know if the col() function belongs to any specific Dataframe library or Python library .I dont want to use pyspark api and would like to write code using sql datafra...Hi Oli, Thank you, thats pointed me the right way. The entire code for my experiment is: #beginning of code for experiment! from psychopy import visual, core, event #import some libraries from PsychoPy trial_timer = core.Clock()PySpark pyspark.sql.types.ArrayType (ArrayType extends DataType class) is used to define an array data type column on DataFrame that holds the same type of elements, In this article, I will explain how to create a DataFrame ArrayType column using pyspark.sql.types.ArrayType class and applying some SQL functions on the array …I have a function all_purch_spark() that sets a Spark Context as well as SQL Context for five different tables. The same function then successfully runs a sql query against an AWS Redshift DB. ... NameError: name 'sqlContext' is not defined ...Pyspark offical website Why the Nameerror: name ‘spark’ is not defined Now let us know the some causes for getting the Nameerror: name ‘spark’ error. Cause 1: Misspelled …NameError: name 'sc' is not defined. This is saying that the 'sc' is not defined in the program and due to this program can't be executed. So, in your pyspark program you have to first define SparkContext and store the object in a variable called 'sc'. By default developers are using the name 'sc' for SparkContext object, but if you whish you ...Dec 26, 2016 · There is nothing special in lambda expressions in context of Spark. You can use getTime directly: spark.udf.register ('GetTime', getTime, TimestampType ()) There is no need for inefficient udf at all. Spark provides required function out-of-the-box: spark.sql ("SELECT current_timestamp ()") or. When you are using Jupyter 4.1.0 or Jupyter 5.0.0 notebooks with Spark version 2.1.0 or higher, only one Jupyter notebook kernel can successfully start a SparkContext. All subsequent kernels are not able to start a SparkContext ( sc ). If you try to issue Spark commands on any subsequent kernels without stopping the running kernel, you ...This code works as written outside of a Jupyter notebook, I believe the answers you want can be found here.Multiprocessing child threads need to be able to import the __main__ script, and I believe Jupyter loads your script as a module, meaning the child processes don't have access to it. You need to move the workers to another module and …Yes, I have. INSTALLED_APPS= ['rest_framework'] django restframework is already installed and I have added both est_framework and my application i.e. restapp in INSTALLED_APPS too. first of all change you class name to uppercase Employee, and you are using ModelSerializer, why you using esal=serializers.FloatField (required=False), …Jun 6, 2015 · 2 Answers. from pyspark import SparkConf, SparkContext from pyspark.sql import SQLContext conf = SparkConf ().setAppName ("building a warehouse") sc = SparkContext (conf=conf) sqlCtx = SQLContext (sc) Hope this helps. sc is a helper value created in the spark-shell, but is not automatically created with spark-submit. With Spark 2.0 a new class SparkSession ( pyspark.sql import SparkSession) has been introduced. SparkSession is a combined class for all different …Oct 23, 2020 · Getting two errors with my Databricks Spark script with the following line: df = spark.createDataFrame(pdDf).withColumn('month', substring(col('dt'), 0, 7)) The first one: AttributeError: 'Series' object has no attribute 'substr' and. NameError: name 'substr' is not defined I wonder what I am doing wrong... Python NameError: name is not defined; But since the class and function are both defined in the correct order in the script I copied, there must be something else going on. python; python-2.7; api; jupyter; jupyter-notebook; Share. Improve this question. Follow edited May 23, 2017 at 12:23. Community Bot. 1 1 1 silver badge. asked Jan 30, …Error: Add a column to voter_df named random_val with the results of the F.rand() method for any voter with the title Councilmember. Set random_val to 2 for the Mayor. Set any other title to the value 0Sorted by: 59. You've imported datetime, but not defined timedelta. You want either: from datetime import timedelta. or: subtract = datetime.timedelta (hours=options.goback) Also, your goback parameter is defined as a string, but then you pass it to timedelta as the number of hours. You'll need to convert it to an integer, or …# Get the sequence of the 1qg8 PDB file, and write to an alignment file1 Answer. You need from numpy import array. This is done for you by the Spyder console. But in a program, you must do the necessary imports; the advantage is that your program can be run by people who do not have Spyder, for instance. I am not sure of what Spyder imports for you by default. array might be imported through from pylab import * or ...4. This issue could be solved by two ways. If you try to find the Null values from your dataFrame you should use the NullType. Like this: if type (date_col) == NullType. Or you can find if the date_col is None like this: if date_col is None. I hope this help.NameError: name 'datetime' is not defined. Maybe this is because the Pyspark foreach function works with pickled objects? ... Error: TimestampType can not accept object while creating a Spark dataframe from a list. 1 TypeError: Can not infer schema for type: <class 'datetime.timedelta'> ...Jun 18, 2022 · PySpark: NameError: name 'col' is not defined. I am trying to find the length of a dataframe column, I am running the following code: from pyspark.sql.functions import * def check_field_length (dataframe: object, name: str, required_length: int): dataframe.where (length (col (name)) >= required_length).show () Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about TeamsTeams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about TeamsI' ve searched Stack resoures BTW and I didn't find anything. Take a look at the start of the section 1.1.3. You have to type first from string import *. >>> from string import* >>> nb_a = count (seq, 'a') Traceback (most recent call last): File "<pyshell#73>", line 1, in <module> nb_a = count (seq, 'a') NameError: name 'count' is not defined ...Replace “/path/to/spark” with the actual path where Spark is installed on your system. 3. Setting Environment Variables. Check if you have set the SPARK_HOME environment variable. Post Spark/PySpark installation you need to set the SPARK_HOME environment variable with the installationI'll end the suspense -- this is a mistake but not a syntax error, since in Python using a name that hasn't been defined isn't a syntax error, it's a perfectly well-defined code snippet in the language. It's just that it's defined to throw an exception, which isn't what the questioner wants to do. –Feb 11, 2013 · Add a comment. 23. Note that sometimes you will want to use the class type name inside its own definition, for example when using Python Typing module, e.g. class Tree: def __init__ (self, left: Tree, right: Tree): self.left = left self.right = right. This will also result in. NameError: name 'Tree' is not defined. Nov 22, 2019 · df.persist(pyspark.StorageLevel.MEMORY_ONLY) NameError: name 'MEMORY_ONLY' is not defined df.persist(StorageLevel.MEMORY_ONLY) NameError: name 'StorageLevel' is not defined import org.apache.spark.storage.StorageLevel ImportError: No module named org.apache.spark.storage.StorageLevel Any help would be greatly appreciated. I don't think this is the command to be used because Python can't find the variable called spark.spark.read.csv means "find the variable spark, get the value of its read attribute and then get this value's csv method", but this fails since spark doesn't exist. This isn't a Spark problem: you could've as well written nonexistent_variable.read.csv. – …1 Answer. You are using the built-in function 'count' which expects an iterable object, not a column name. You need to explicitly import the 'count' function with the same name from pyspark.sql.functions. from pyspark.sql.functions import count as _count old_table.groupby ('name').agg (countDistinct ('age'), _count ('age'))Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teamspyspark : NameError: name 'spark' is not defined. 1 NameError: global name 'dot_parser' is not defined / PydotPlus / Pyparsing 2 / Anaconda. Load 4 more related questions Show fewer related questions Sorted by: Reset to default Know someone who can answer? Share a link to this ...Difference between “nameerror: name ‘list’ is not defined” and “nameerror: name ‘List’ is not defined” The difference between “List” and “list” is that “List” refers to the typing module’s List type hint, which is used to annotate lists, while ‘list‘ refers to the built-in Python list data type.pyspark : NameError: name 'spark' is not defined. I am copying the pyspark.ml example from the official document website: http://spark.apache.org/docs/latest/api/python/pyspark.ml.html#pyspark.ml.Transformer.I'm using a notebook within Databricks. The notebook is set up with python 3 if that helps. Everything is working fine and I can extract data from Azure Storage. However when I run: import org.apa...Feb 7, 2023 · Note: Do not use Python shell or Python command to run PySpark program. 2. Using findspark. Even after installing PySpark you are getting “No module named pyspark" in Python, this could be due to environment variables issues, you can solve this by installing and import findspark. PySpark April 25, 2023 3 mins read Problem: When I am using spark.createDataFrame () I am getting NameError: Name 'Spark' is not Defined, if I use the same in Spark or …You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Reload to refresh your session. You switched accounts on another tab or window.which will open your contents in a new browser. I'm not sure about Streamlit, but I know that there is None instead of null in Python. You can try to define null = None in your script C:\Users\cupac\desktop\untitled.py at the top - it might work! As it’s currently written, your answer is unclear.To check the spark version you have enter (in cmd): spark-shell --version. And, to check Pyspark version enter (in cmd): pip show pyspark. After that, Use the following code to create SparkContext : conf = pyspark.SparkConf () sqlcontext = pyspark.SparkContext.getOrCreate (conf=conf) sc = SQLContext (sqlcontext) after that …The above code works perfectly on Jupiter notebook but doesn't work when trying to run the same code saved in a python file with spark-submit I get the following errors. NameError: name 'spark' is not defined. when i replace spark.read.format("csv") with sc.read.format("csv") I get the following errorBut then inside a udf you can not directly use spark functions like to_date. So I created a little workaround in the solution. So I created a little workaround in the solution. First the udf takes the python date conversion with the appropriate format from the column and converts it to an iso-format.Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about TeamsHow many terms do you want for the sequence? 5 Traceback (most recent call last): File "fibonacci.py", line 18, in <module> n = calculate_nt_term(n1, n2) NameError: name 'calculate_nt_term' is not defined. Python cannot find the name “calculate_nt_term” in the program because of the misspelling.I don't know. If pyspark is a separate kernel, you should be able to run that with nbconvert as well. Try using the option --ExecutePreprocessor.kernel_name=pyspark. If it's still not working, ask …1 1. 1. Please use the "code sample" feature to show code snippets. Avoid sending screenshots. – Foivoschr. May 10, 2020 at 8:34. I think code part that have the problem is not present on the screenshot. Seems like you're using variable/function that you didn't define/import. – Rayan Ral.I solved defining the following helper function in my model's module: from uuid import uuid4 def generateUUID (): return str (uuid4 ()) then: f = models.CharField (default=generateUUID, max_length=36, unique=True, editable=False) south will generate a migration file (migrations.0001_initial) with a generated UUID like: default='5c88ff72-def3 ...Jan 10, 2024 · Replace “/path/to/spark” with the actual path where Spark is installed on your system. 3. Setting Environment Variables. Check if you have set the SPARK_HOME environment variable. Post Spark/PySpark installation you need to set the SPARK_HOME environment variable with the installation 17. When executing Python scripts, the Python interpreter sets a variable called __name__ to be the string value "__main__" for the module being executed (normally this variable contains the module name). It is common to check the value of this variable to see if your module is being imported for use as a library, or if it is being executed ... 2 days back I could run pyspark basic actions. noYou've got to use self. Or, if you want to be explicit1. df ['timestamp'] = [datetime.datetime.fromtimestamp (d)

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Python NameError: name is not defined; But since the class and function are both defined in the correct order in the script I copied, there must be something else going on. python; python-2.7; api; jupyter; jupyter-notebook; Share. Improve this question. Follow edited May 23, 2017 at 12:23. Community Bot. 1 1 1 silver badge. asked Jan 30, …Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'sc' is not defined I have tried: ... name spark is not defined. 1. sc is not defined in SparkContext. 0. Name sc is not defined. Hot Network Questions How does the law deal with translating inherently ambiguous writing systems?SparkSession.createDataFrame(data, schema=None, samplingRatio=None, verifySchema=True)¶ Creates a DataFrame from an RDD, a list or a pandas.DataFrame.. When schema is a list of column names, the type of each column will be inferred from data.. When schema is None, it will try to infer the schema (column names and types) from …3 Answers. Sorted by: 2. Your specific issue of NameError: name 'guess' is not defined is because guess is defined in your main function, but the while loop that it is failing on is outside of that function. Your indention is entirely wrong for this application. If you want your while guess != number: to work, you need to make it part of main.This means that if you try to evaluate an expression that is just match, it will not be treated as a match statement, but as a variable called match, which isn't defined in your case (no pun intended). Try writing a complete match statement. Thanks this works! A complete match statement is required.Aug 21, 2019 · I m executing the below code and using Pyhton in notebook and it appears that the col() function is not getting recognized . I want to know if the col() function belongs to any specific Dataframe library or Python library .I dont want to use pyspark api and would like to write code using sql datafra... PySpark lit () function is used to add constant or literal value as a new column to the DataFrame. Creates a [ [Column]] of literal value. The passed in object is returned directly if it is already a [ [Column]]. If the object is a Scala Symbol, it is converted into a [ [Column]] also. Otherwise, a new [ [Column]] is created to represent the ..."name 'spark' is not defined" Using Python version 2.6.6 (r266:84292, Nov 22 2013 12:16:22) SparkContext available as sc. >>> import pyspark >>> textFile = spark.read.text("README.md") Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'spark' is not defined registerFunction(name, f, returnType=StringType)¶ Registers a python function (including lambda function) as a UDF so it can be used in SQL statements. In addition to a name …Post the relevant code that calls quit (). You are calling the function quit () under pygame.quit () at line 42 on the codepen that is not defined in your program. Create the function or remove the line. quit always fails for me too when freezing. Use sys.exit () instead.2 days back I could run pyspark basic actions. now spark context is not available sc. I tried multiple blogs but nothing worked. currently I have python 3.6.6, java 1.8.0_231, and apache spark( with ... (most recent call last) <ipython-input-2-572751a2bc2a> in <module> ----> 1 data = sc.textfile('airline.csv') NameError: name 'sc' …I'm very new to programming. I've been trying to learn Python via a book called "Python Programming for the Absolute Beginner". I'm working on classes. I've copied some code from one of the exer...I use this code to return the day name from a date of type string: import Pandas as pd df = pd.Timestamp("2019-04-10") print(df.weekday_name) so when I have "2019-04-10" the code returns "Wednesday" I would like to apply it a column in Pyspark DataFrame to get the day name in text. But it doesn't seem to work.To access the DBUtils module in a way that works both locally and in Azure Databricks clusters, on Python, use the following get_dbutils (): def get_dbutils (spark): try: from pyspark.dbutils import DBUtils dbutils = DBUtils (spark) except ImportError: import IPython dbutils = IPython.get_ipython ().user_ns ["dbutils"] return dbutils.As of databricks runtime v3.0 the answer provided by pprasad009 above no longer works. Now use the following: def get_dbutils (spark): dbutils = None if spark.conf.get ("spark.databricks.service.client.enabled") == "true": from pyspark.dbutils import DBUtils dbutils = DBUtils (spark) else: import IPython dbutils = IPython.get_ipython ().user_ns ... 1. df ['timestamp'] = [datetime.datetime.fromtimestamp (d) for d in df.time] I think that line is the problem. Your Dataframe df at the end of the line doesn't have the attribute .time. For what it's worth I'm on Python 3.6.0 and this runs perfectly for me: import requests import datetime import pandas as pd def daily_price_historical (symbol ...Apr 25, 2016 · Teams. Q&A for work. Connect and share knowledge within a single location that is structured and easy to search. Learn more about Teams Nov 14, 2016 · 2 Answers. If you are using Apache Spark 1.x line (i.e. prior to Apache Spark 2.0), to access the sqlContext, you would need to import the sqlContext; i.e. from pyspark.sql import SQLContext sqlContext = SQLContext (sc) If you're using Apache Spark 2.0, you can just the Spark Session directly instead. Therefore your code will be. Solution 1: Import the required module. Ensure you imported the required module that defines the “sqlcontext” variable. In the case of Apache Spark, the module that usually used is pyspark.sql. By importing the sqlcontext class from the pyspark.sql module, by doing so, you can access the “sqlcontext” variable and perform SQL operations ...NameError: name 'countryCodeMap' is not defined. I am trying to implement a Spark program in a Databricks Cluster and I am following the documentation whose link is as follows: def mapKeyToVal (mapping): def mapKeyToVal_ (col): return mapping.get (col) return udf (mapKeyToVal_, StringType ())"name 'spark' is not defined" Using Python version 2.6.6 (r266:84292, Nov 22 2013 12:16:22) SparkContext available as sc. >>> import pyspark >>> textFile = spark.read.text("README.md") Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'spark' is not defined >>> b = a Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'a' is not defined It is important to know that very few Python commands will "magically" create names. To create a name, you would almost always need an assignment (name = ...). So as a general rule if you you haven't done this, name will1 Answer. You need from numpy import array. This is done for you by the Spyder console. But in a program, you must do the necessary imports; the advantage is that your program can be run by people who do not have Spyder, for instance. I am not sure of what Spyder imports for you by default. array might be imported through from pylab import * or ... Mar 27, 2022 · I don't think this is the command to be used because Python can't find the variable called spark. spark.read.csv means "find the variable spark, get the value of its read attribute and then get this value's csv method", but this fails since spark doesn't exist. This isn't a Spark problem: you could've as well written nonexistent_variable.read.csv. which will open your contents in a new browser. I'm not sure about Streamlit, but I know that there is None instead of null in Python. You can try to define null = None in your script C:\Users\cupac\desktop\untitled.py at the top - it might work! As it’s currently written, your answer is unclear.You signed in with another tab or window. Reload to refresh your session. You signed out in another tab or window. Reload to refresh your session. You switched accounts on another tab or window.Error: Add a column to voter_df named random_val with the results of the F.rand() method for any voter with the title Councilmember. Set random_val to 2 for the Mayor. Set any other title to the value 0Reloading module giving NameError: name 'reloPySpark April 25, 2023 3 mins read Problem: When I

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2 days back I could run pyspark basic actions. now spark context is not available sc. I tried multiple blogs but nothing worked. currently I have python 3.6.6, java 1.8.0_231, and apache spark( with ... (most recent call last) <ipython-input-2-572751a2bc2a> in <module> ----> 1 data = sc.textfile('airline.csv') NameError: name 'sc' …Jan 19, 2014 · I solved defining the following helper function in my model's module: from uuid import uuid4 def generateUUID (): return str (uuid4 ()) then: f = models.CharField (default=generateUUID, max_length=36, unique=True, editable=False) south will generate a migration file (migrations.0001_initial) with a generated UUID like: default='5c88ff72-def3 ... 4. This issue could be solved by two ways. If you try to find the Null values from your dataFrame you should use the NullType. Like this: if type (date_col) == NullType. Or you can find if the date_col is None like this: if date_col is None. I hope this help.registerFunction(name, f, returnType=StringType)¶ Registers a python function (including lambda function) as a UDF so it can be used in SQL statements. In addition to a name …Convert Spark SQL Dataframe to Pandas Dataframe. I'm current using a Databricks notebook, intially in Scala, using JDBC to connect to a SQL server and return a table. i use the following code to query and display the table within the notebook. val ViewSQLTable= spark.read.jdbc (jdbcURL, "api.meter_asset_enquiry", …NameError: name 'spark' is not defined. The text was updated successfully, but these errors were encountered: All reactions. Copy link Collaborator. gbrueckl commented May 2, 2020 via email . That's actually related to Databricks-connect and has nothing to do with this extension When a notebook is executed within the …Yes, I have. INSTALLED_APPS= ['rest_framework'] django restframework is already installed and I have added both est_framework and my application i.e. restapp in INSTALLED_APPS too. first of all change you class name to uppercase Employee, and you are using ModelSerializer, why you using esal=serializers.FloatField (required=False), …Aug 10, 2020 · 1 Answer. Inside the pyspark shell you automatically only have access to the spark session (which can be referenced by "spark"). To get the sparkcontext, you can get it from the spark session by sc = spark.sparkContext. Or using the getOrCreate () method as mentioned by @Smurphy0000 in the comments. Version is an attribute of the spark context. 23. If you are using Apache Spark 1.x line (i.e. prior to Apache Spark 2.0), to access the sqlContext, you would need to import the sqlContext; i.e. from pyspark.sql import SQLContext sqlContext = SQLContext (sc) If you're using Apache Spark 2.0, you can just the Spark Session directly instead. Therefore your code will be.1. In pysparkShell, SparkContext is already initialized as SparkContext (app=PySparkShell, master=local [*]) so you just need to use getOrCreate () to set the SparkContext to a variable as. sc = SparkContext.getOrCreate () sqlContext = SQLContext (sc) For coding purpose in simple local mode, you can do the following.try: # Python 2 forward compatibility range = xrange except NameError: pass # Python 2 code transformed from range (...) -> list (range (...)) and # xrange (...) -> range (...). The latter is preferable for codebases that want to aim to be Python 3 compatible only in the long run, it is easier to then just use Python 3 syntax whenever possible ...Adding dictionary keys as column name and dictionary value as the constant value of that column in Pyspark df 0 How to add a completely irrelevant column to a data frame when using pyspark, spark + databricks Solution 2: Use alias for the col function. If you want to use another name for the “col” function, you can import it with an alias by using the following line at the top or beginning of your script. For example: from pyspark.sql.functions import col as column. This solution allows you to use the column function in your code instead of ...How to Fix NameError: name 'x' is not defined | Solution. variable is passed as an argument to the function when it is called. This ensures that the. Get a clear explanation …This answer is not useful. Save this answer. Show activity on this post. FindSpark module will come handy here. Install the module with the following: python -m pip install findspark. Make sure SPARK_HOME environment variable is set. Usage: import findspark findspark.init () import pyspark # Call this only after findspark from pyspark.context ... Apr 25, 2023 · If you are getting Spark Context 'sc' Not Defined in Spark/PySpark shell use below export. export PYSPARK_SUBMIT_ARGS="--master local [1] pyspark-shell". vi ~/.bashrc , add the above line and reload the bashrc file using source ~/.bashrc and launch spark-shell/pyspark shell. Below is a way to use get SparkContext object in PySpark program. I'm using a notebook within Databricks. The notebook is set up with python 3 if that helps. Everything is working fine and I can extract data from Azure Storage. However when I run: import org.apa...NameError: name 'sc' is not defined. This is saying that the 'sc' is not defined in the program and due to this program can't be executed. So, in your pyspark program you have to first define SparkContext and store the object in a variable called 'sc'. By default developers are using the name 'sc' for SparkContext object, but if you whish you ...I have installed the Apache Spark provider on top of my exiting Airflow 2.0.0 installation with: pip install apache-airflow-providers-apache-spark When I start the webserver it is unable to import ...Add a comment. -1. The first thing a Spark program must do is to create a SparkContext object, which tells Spark how to access a cluster. To create a SparkContext you first need to build a SparkConf object that contains information about your application. conf = SparkConf ().setAppName (appName).setMaster (master) sc = SparkContext …Reloading module giving NameError: name 'reload' is not defined. 72 Python NameError: name is not defined. Load 6 more related questions Show fewer related …Feb 11, 2013 · Add a comment. 23. Note that sometimes you will want to use the class type name inside its own definition, for example when using Python Typing module, e.g. class Tree: def __init__ (self, left: Tree, right: Tree): self.left = left self.right = right. This will also result in. NameError: name 'Tree' is not defined. There is nothing special in lambda expressions in context of Spark. You can use getTime directly: spark.udf.register ('GetTime', getTime, TimestampType ()) There is no need for inefficient udf at all. Spark provides required function out-of-the-box: spark.sql ("SELECT current_timestamp ()") or.You are not calling your udf the right way, it's either register a udf and then call it inside .sql("..") query or create udf() on your function and then call it inside your .withColumn(), I fixed your code:Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'sc' is not defined I have tried: ... name spark is not defined. 1. sc is not defined in SparkContext. 0. Name sc is not defined. Hot Network Questions How does the law deal with translating inherently ambiguous writing systems?I' ve searched Stack resoures BTW and I didn't find anything. Take a look at the start of the section 1.1.3. You have to type first from string import *. >>> from string import* >>> nb_a = count (seq, 'a') Traceback (most recent call last): File "<pyshell#73>", line 1, in <module> nb_a = count (seq, 'a') NameError: name 'count' is not defined ...Nov 11, 2019 · The simplest to read csv in pyspark - use Databrick's spark-csv module. from pyspark.sql import SQLContext sqlContext = SQLContext(sc) df = sqlContext.read.format('com.databricks.spark.csv').options(header='true', inferschema='true').load('file.csv') Also you can read by string and parse to your separator. Your formatting is off in the StackOverflow post here, in that the "class User" line is outside the preformatted code block, and all the class's methods are indented at the wrong level. You want something like: class User (): def __init__ (self): return def another_method (self): return john = User ('john') Share. Improve this answer. Follow. When I try tokens = cleaned_book(flatMap(normalize_tokeniz